2 years ago

Hallllp!!!! please!!!!!!! I will give brainliest!!!!

Mathematics

1 answer:

KonstantinChe [14]2 years ago

8 0

A. Product of a constant factor 12 and two-term factor x+3

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Answer:

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$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

$X \sim Binom(n=2, p=0.01)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(x \geq 1)=1-P(X$

And we can find the probability:

$P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801$

And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

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