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shusha [124]
3 years ago
5

Hallllp!!!! please!!!!!!! I will give brainliest!!!!

Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0
A. Product of a constant factor 12 and two-term factor x+3
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A large container holds 8 gallons of water. It begins leaking at a constant rate. After 32 minutes the container has 6 gallons l
anzhelika [568]

Answer:

1 gallon every 16 minutes

Step-by-step explanation:

If after 32 minutes the container has 6 gallons left that means it has lost 2 gallons of water. So we now divide the 32 minutes by the 2 gallons of water to get that 1 gallon of water leaks every 16 minutes.


8 0
3 years ago
Please give me the answer and show me how you solved it
Yuri [45]

Answer:

Option 1: -8c^8

Step-by-step explanation:

We multiply the numbers by the numbers, then the variables times the variables.

-2 times 4 gives us -8

c^3 times c^5 = c ^8. When multiplying a variable with exponents, you add the exponents.

You only multiply the exponents when it's something like (c^3)^5

4 0
3 years ago
What is the value of x in the model below? <br> Enter your answer in the box.
sp2606 [1]

It looks like the scale is balanced so that means you can set one side equal to the other which leaves you with the equation x+(-10)=-16

To get x by itself add x to each side to get x=-6

X=-6 is your answer

3 0
3 years ago
Read 2 more answers
Check ALL of the ratios that are equivalent to 5:8 (Select al that apply) 10:16 8:5 2.5:4 40:25 15 to 24​
zlopas [31]

Answer:

10 ,16 AND 8

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST

4 0
3 years ago
Read 2 more answers
If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
andreev551 [17]
Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
8 0
3 years ago
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