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3 years ago

X 50 50 X = degrees Please help with this problem I am going crazy

Mathematics

2 answers:

zhuklara [117]3 years ago

7 0

Answer:

x = 80°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for x

x = 180° - (50 + 50)° = 180° - 100° = 80°

sveta [45]3 years ago

6 0

Answer:

x=80°

Step-by-step explanation:

Triangles always add up to 180°.

As you have 2 angles, you would have to add them together and then take it away from 180° to get your answer.

50+50=100°

180-100=80°

Hope this helps :)

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3 years ago

The local bike shop sells a bike and accessories package for $276. If the bike is worth 5 times more than the accessories, how m

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3 years ago

Two families went to Rollercoaster World.

Alona [7]

Answer:

Children ticket cost $30 and adult ticket costs $40.

Step-by-step explanation:

Given that:

x = price of a child ticket

y = price of an adult ticket

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6 0

3 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

4 years ago