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koban [17]
3 years ago
7

Solve the following system of equations. 18x+6y=3018x+6y=30 18x+22y=1418x+22y=14

Mathematics
1 answer:
Triss [41]3 years ago
4 0

Answer:

  • (2, -1)

Step-by-step explanation:

<u>Given system</u>

  • 18x+6y=30  
  • 18x+22y=14

<u>Solve by elimination, subtract the equations and solve for y:</u>

  • 18x + 6y - 18x - 22y = 30 - 14
  • -16y = 16
  • y = -1

<u>Find x by substituting y:</u>

  • 18x + 6(-1) = 30
  • 18x - 6 = 30
  • 18x = 36
  • x = 36/18
  • x = 2

<u>The answer is</u>: (2, -1)

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Answer:

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Answer:

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Step-by-step explanation:

In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....

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