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xenn [34]
2 years ago
14

Factorize the following 4x+16y+24z

Mathematics
1 answer:
FrozenT [24]2 years ago
6 0
  • 4x + 16y + 24z
  • = 4(x + 4y + 6z)

<u>Answer</u><u>:</u>

<u>4</u><u>(</u><u>x </u><u>+</u><u> </u><u>4</u><u>y</u><u> </u><u>+</u><u> </u><u>6</u><u>z</u><u>)</u>

Hope you could understand.

If you have any query, feel free to ask

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A rental car agency charges a flat fee of $32.00 plus $3.00 per day to rent a certain car. Another agency charges a fee of $30.5
diamong [38]

Answer:

a rental car agency charges a flat rate fee of $32.00 plus $3.00 per day to rent a certain car

c = 32 + 3d

another agency charges a fee of $30.50 plus $3.25 per day to rent the same car

c = 30.50 + 3.25d

the number of days for which the cost are the same means

32 + 3d = 30.50 + 3.25d

by solving we find   d = 6 days

5 0
3 years ago
To make 5 blueberry pies, Mindy needs about 2 pounds of blueberries. How many pounds of blueberries does Mindy need to make 20 b
gavmur [86]

Answer:

8 pounds

Step-by-step explanation:

20/5=4

2*4=8

hope this helps :3

if it did pls mark brainliest

5 0
3 years ago
Read 2 more answers
Find the product of (x+3) (x+3)
MA_775_DIABLO [31]

Answer:

x^{2} + 9x

Step-by-step explanation:

(x+3)(x+3)

distribute the x to both three and x.

x * x + 3x * 3x

add like terms.

X^2 + 9x

7 0
3 years ago
1.2, 3, 7.5, 18.75, ...<br><br> Which formula can be used to describe the sequence?
Nady [450]

Answer:

The formula is:

a_n=1.2(\frac{5}{2})^{n-1}

Step-by-step explanation:

The geometric sequences are those in which the division between the terms a_{n + 1} and a_n of the sequence are equal to a constant common reason called "r"

The geometrics secencias have the following form:

a_n=a_1(r)^{n-1}

Where a_1 is the first term of the sequence

In this sequence we have the following terms

1.2, 3, 7.5, 18.75

Then notice that:

\frac{3}{1.2}=\frac{5}{2}\\\\\frac{7.5}{3}=\frac{5}{2}\\\\\frac{18.75}{7.5}=\frac{5}{2}

Then:

r=\frac{5}{2}  and a_1=1.2

Finally the formula is:

a_n=1.2(\frac{5}{2})^{n-1}

5 0
3 years ago
Read 2 more answers
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
3 0
4 years ago
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