Factorize the following 4x+16y+24z
1 answer:
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A segment is bounded by two endpoints.
The two segments can have up to two common points
Assume the line segments are AB and CD where the length of AB is greater than the length of CD.
<u>The possibilities are:</u>
- <em>A point of segment CD lies on segment AB</em>
- <em>Both points of segment CD lie on segment AB.</em>
<em />
See attachment for both possibilities.
Hence, it is possible for the two segments to have two common points.
Read more about line segments at:
We need to notice that SSSS does not exist as a method to prove that parallelograms are congruent
Counterexample
As we can see we have the same measure of the side of the intern angles of the figures are different therefore we can't use SSSS to prove congruence
