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3 years ago

PLS HELP ASAP!!!!!!!!!

Mathematics

1 answer:

jeka943 years ago

6 0

Answer: A, C and E

Step-by-step explanation:

because there are 2 shapes in which have the same formula height times base so 6 is the base and n and m is both of the heights but they are the same height so you need to add them for the total height then mutiply the total height by 6 which means you can ALSO do 6n and 6m because if n=5 and m=2 6x5=30+6x2=12=42 and 6x(5+2)=42 and you can switch the equations around getting the same answer AND B is wrong because 6x5=30+2=32 NOT 42 and D is wrong because 6x5x2=60 not 42 SO it has to be A, C and E

plz mark be brainliest

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Vesna [10]

Answer:

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Step-by-step explanation:

Given the expression

$\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}\:=\:x^{a-b}$

$\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=\left(\frac{2}{54}\right)^{-\frac{4}{3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\frac{1}{\left(\frac{2}{54}\right)^{\frac{4}{3}}}$

$=\left(\frac{1}{27}\right)^{-\frac{4}{3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}$

$=\frac{1}{\frac{1^{\frac{4}{3}}}{27^{\frac{4}{3}}}}$

$=\frac{1}{\frac{1^{\frac{4}{3}}}{81}}$ ∵ $27^{\frac{4}{3}}=81$

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$=\frac{81}{1^{\frac{1}{3}}}$

$\mathrm{Apply\:rule}\:1^a=1$

$=\frac{81}{1}$

$=81$

Therefore, we conclude that:

$\frac{2^{-\frac{4}{3}}}{54^{-\frac{4}{3}}}=81$

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