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3 years ago

8

The sum of the digits of a two digit number and the number reversed is 34. The difference of the number and the number with the

digits reversed is 36. Find the original number.

1 answer:

maw [93]3 years ago

8 0

Answer:

original number: 62

Step-by-step explanation:

number: xy

(x+y) + (10y+x) = 34

2x + 11y = 34 (1)

(10x+y) - (10y+x) = 36

9x - 9y = 36

x - y = 4

x = y + 4

2* (y+4) + 11y = 34 (substitute (1))

13y + 8 = 34

13y = 26

y = 2

x = 6

Number: 62

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GIVING OUT BRAINLIEST TO WHOEVER GETS ALL OF THEM RIGHT

Thepotemich [5.8K]

Answer:

4) $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

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6) $\frac{x+7}{x^{2}+4\cdot x - 21}$ is equivalent to $\frac{1}{x-3}$ for all $x \ne 3$ . (Answer: None)

7) $\frac{x^{2}+3\cdot x -4}{x+4}$ is equivalent to $x - 1$ . (Answer: None)

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Step-by-step explanation:

We proceed to simplify each expression below:

4) $\frac{x}{7\cdot x +x^{2}}$

(i) $\frac{x}{7\cdot x +x^{2}}$ Given

(ii) $\frac{x}{x\cdot (7+x)}$ Distributive property

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Rational functions are undefined when denominator equals 0. That is:

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Hence, we conclude that $\frac{x}{7\cdot x +x^{2}}$ is equivalent to $\frac{1}{7+x}$ for all $x \ne -7$ . (Answer: A)

5) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$

(i) $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ Given

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(iii) $\frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right)$ Distributive property

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Rational functions are undefined when denominator equals 0. That is:

$1-5\cdot x = 0$

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$x = \frac{1}{5}$

Hence, we conclude that $\frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}$ is equivalent to $-\frac{14}{1-5\cdot x}$ for all $x \ne \frac{1}{5}$ . (Answer: B)

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$x-3 = 0$

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(i) $\frac{x^{2}+3\cdot x -4}{x+4}$ Given

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