If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
Answer: B. Between 150 and 200
Parent Function: f(x)=x*2
Horizontal Shift: None
Vertical Shift: Down 1 Units
Reflection about the x-axis: None
Reflection about the y-axis: None
Vertical Compression or Stretch: None
There should be a number of students in 2012
just do 1.2*number of students in 2012 to get the answer
The answer is attached in the photo
