All categories

2 years ago

What types of shapes will tessellate?

2 answers:

8 0

Only three regular polygons (shapes with all sides and angles equal) can form a tessellation by themselves—triangles, squares, and hexagons.

Sedbober [7]2 years ago

3 0

Answer: D

Step-by-step explanation:

You might be interested in

It says solution to the equation as a decimal q-1.8+1.8=14+1.8

Zielflug [23.3K]

Q-1.8+1.8=14+1.8= Q=15.8 hope this helps

6 0

3 years ago

What is 100 minus X is less than 41

olga55 [171]

X can be anything greater than 59 or x>59

6 0

4 years ago

Read 2 more answers

Find the slope and reduce. P=(2, 3) Q=(9, 7) Slope =

son4ous [18]

Answer:

Step-by-step explanation:

(7 - 3)/(9 - 2) = 4/7

7 0

3 years ago

Triangle QRS has vertices Q(-4,2),R(3,0), and S(4,3).

Dafna1 [17]

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

Vectorially speaking, a point is translated to another location on Cartesian plane by means of this expression:

$A'(x,y) = A(x,y) + T(x,y)$ (1)

Where:

$A(x,y)$ - Original point.
$A'(x,y)$ - Translated point.
$T(x,y)$ - Translation vector.

If we know that $Q(x,y) = (-4,2)$ , $R(x,y) = (3,0)$ , $S(x,y) = (4, 3)$ and $R'(x,y) = (7, -6)$ $T(x,y) = (4, -6)$ , then the coordinates of the vertices of the triangle $Q'R'S'$ are:

$Q'(x,y) = Q(x,y) + T(x,y)$

$Q'(x,y) = (-4,2) + (4,-6)$

$Q'(x,y) = (0, -4)$

$R'(x,y) = R(x,y) + T(x,y)$

$R'(x,y) = (3,0) +(4,-6)$

$R'(x,y) = (7,-6)$

$S'(x,y) = S(x,y) + T(x,y)$

$S'(x,y) = (4, 3) + (4, -6)$

$S'(x,y) = (8, -3)$

The coordinates of the vertices of $\triangle Q'R'S'$ are $Q'(x,y) = (0, -4)$ , $R'(x,y) = (7,-6)$ and $S'(x,y) = (8, -3)$ , respectively.

We kindly invite to see this question on translations: brainly.com/question/17485121

5 0

3 years ago

What is 207.4÷61pls help

sesenic [268]

3.4 is the answer (rounded up of course)

5 0

3 years ago

Read 2 more answers