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zloy xaker [14]
3 years ago
12

Please help :) find the area of the regular polygon

Mathematics
1 answer:
viva [34]3 years ago
8 0

9514 1404 393

Answer:

  3√3 square units

Step-by-step explanation:

The area of a regular n-sided polygon with radius r is given by the formula ...

  A = (n/2)r²·sin(360°/n)

For n=3 and r=2, the area is ...

  A = (3/2)(2²)·sin(360°/3) = 6·sin(120°) = 6(√3/2)

  A = 3√3 . . . . square units

_____

<em>Alternate solution</em>

The center of this polygon is the centroid, which divides each median into parts with the ratio 2:1. This means the given radius is 2/3 of the height of the triangle. The base of the triangle is 2/√3 times the height, so is ...

  b = (2/√3)(3) = 2√3

The area using these dimensions is calculated as ...

  A = 1/2bh

  A = 1/2(2√3)(3) = 3√3 . . . . square units

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Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
3 years ago
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Y_Kistochka [10]
I don't do good with slope intercept, but I can tell you that Fit n Trim would be $80m and Fit for Life would be $75+55m. 
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2 years ago
The function f(x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2,–1)} Which equation is true? f of ne
Rudik [331]

Answer:

f(0)=6

Step-by-step explanation:

When representing function's values by set of ordered pairs, the first one correspond to the x value and the second to the image or "y" value.

When you read f(0) means "when x is 0" then the 6 is the value of the function or the image.

7 0
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Answer:

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Step-by-step explanation:

90

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2 years ago
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gladu [14]
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y = (m)x + (b)
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