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3 years ago

15

Plz Help! Need to get through assignment and move on to other lessons.

1 answer:

emmasim [6.3K]3 years ago

5 0

Where is the question

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A population of rabbits at time t increases at a rate of 40-12t+3t^2 rabbits per year where t is measured in years. Find the po

zmey [24]

We have to find derivative of t

$\\ \sf\longmapsto \dfrac{d}{dx}3t^2-12t+4$

$\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}$

$\\ \sf\longmapsto \dfrac{d}{dx}3t^2-\dfrac{d}{dx}12t+\dfrac{d}{dx}40$

$\\ \sf\longmapsto 6t-12$

Now

t=8..

$\\ \sf\longmapsto 6(8)-12$

$\\ \sf\longmapsto 48-12$

$\\ \sf\longmapsto 36$

8 0

2 years ago

‼️would appreciate help

horrorfan [7]

<span>Median of Triangle is </span>a line segment from a vertex to the midpoint of the opposite side.

If segment AE is a median of ΔABC, then
<em><u>segments BE and EC are congruent</u></em><em>
</em>

7 0

2 years ago

On the first play, the football team lost 6 yards. On the second play, the team lost 5 yards. What was their total change in yar

Sliva [168]

Their change in yards is -11 yards

3 0

2 years ago

Read 2 more answers

Please anyone solve this for me..No spam.

Tamiku [17]

Answer:

3096

Step-by-step explanation:

<u>Given:</u>

$3x-\frac{1}{4y}=24$

<u>Rewrite it as:</u>

$3x=\frac{1}{4y}+24$
$x=\frac{1}{12y}+8$

<u>Simplify the expression:</u>

$8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =$
$8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 3x =$
$8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 24 + \frac{1}{4y} =$
$8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2} + 24 =$
$8(384-\frac{1}{24y^2}) + \frac{1}{3y^2} + 24 =$
$8*384-\frac{1}{3y^2} + \frac{1}{3y^2} + 24 =$
$3072+24=$
$3096$

3 0

2 years ago

If u(x)=-2x^2+3 and v(x)=1/x what is the range of (u*v)(x) **the picture should help

nasty-shy [4]

We have that
$u(x)=-2 x^{2} +3 \\ \\ v(x)= \frac{1}{x}$
$u(v(x))=u( \frac{1}{x})=-2( \frac{1}{x} )^{2} +3 \\ u( \frac{1}{x})= \frac{(3 x^{2} -2)}{ x^{2} }$

using a graph tool
see the attached figure

The horizontal asymptote of this function is at <span>y=3</span><span>.
So,
the range of this function is from </span><span>(−∞,3<span>)</span></span>

5 0

2 years ago

Read 2 more answers