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Goshia [24]
3 years ago
8

there is a group of 10 people ordering pizza, each person gets 4 slices, there are 6 slices in each pizza, how much pizza should

they order
Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

20

Step-by-step explanation:

60-40=20

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Bryan has a square parcel of land that is 120 yards long and 120 yards wide. The land is planted with Bermuda grass and surround
Mekhanik [1.2K]
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:

h=√2(120^2))

h=√28800 yd

And the surrounding fencing will just be four times the side length of 120yds so:

s=480yd

So the total fencing needed is:

f=480+√28800 yards

f≈649.71 yd  (to nearest hundredth of a yard)  which is

f≈650 yds  (to nearest whole yard)

But, I wasn't sure, if they just want the diagonal fencing needed then it is just:

f=√28800

f≈170 yds  (to nearest yard)


6 0
3 years ago
Read 2 more answers
Drag the numbers to order them from greatest to least, with the greatest at the top. 5.03709 4.923935 17 12
Bond [772]
I think 4.923935; 5,03709; 12; 17
7 0
2 years ago
3. A ladder is 50 feet and cast a 25 foot shadow. Mark is 6 feet how long would his shadow be?
Gala2k [10]

Answer:

3 feet

Step-by-step explanation:

half his height

6 0
2 years ago
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How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
x2+(y-p)2 = (y+p)2.</span>If we expand all the terms and simplify, we obtain<span>x2 = 4py.</span>

Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

<span>x2 = 4py.</span><span>The graph of the parabola would be the reflection, across the </span>x<span> axis of the parabola in the picture above. A way to describe this is if p > 0, the parabola "opens up" and if p < 0 the parabola "opens down".</span>

Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

<span>y2 = 4px</span><span>where the directrix is the verical line </span>x=-p and the focus is at (p,0). If p > 0, the parabola "opens to the right" and if p < 0 the parabola "opens to the left". The equations we have just established are known as the standard equations of a parabola. A standard equation always implies the vertex is at the origin and the focus is on one of the axes. We refer to such a parabola as a parabola in standard position.

Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

5 0
3 years ago
What is the<br> area of the rhombus?
cluponka [151]

Answer:

Area=36

Step-by-step explanation:

Area of rhombus: diagonal 1 x diagonal 2 divided by 2.

To find the area of a rhombus, you need to find the length of both diagonals(which is the distance between 2 points across from each other).

First, find the distance between -8 and 4 which is 12.

Next, find the distance between -1 and -7 which is 6.

12 x 6 =72

72/2=36

4 0
2 years ago
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