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3 years ago

5

Are these triangles congruent, if so how do you know? Need ASAP

2 answers:

vovikov84 [41]3 years ago

8 0

Answer:

I sure that is congruent SAS

lapo4ka [179]3 years ago

4 0

Answer:

i pretty sure they are congruent

Step-by-step explanation:

they are both the same shape and size

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If a+b =5, b+c=6, c+a=7. then find the value of a

vlabodo [156]

Answer:

a = 3

Step-by-step explanation:

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2 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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3 years ago

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3 years ago

What is 7,390.7 divided by 0.874 ?

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3 years ago

−14 + 6x + 7 − 2x = 1 + 5x<br> please answer this problem with work

maksim [4K]

Let's solve your equation step-by-step.<span><span><span><span><span>− 14 </span>+ <span>6x </span></span>+ 7</span> −<span> 2x </span></span>=<span> 1 + <span>5x</span></span></span>
Step 1: Simplify both sides of the equation.<span><span><span><span><span>−14 </span>+ <span>6x </span></span>+ 7 </span>− <span>2x </span></span>=<span> 1 +<span> 5x</span></span></span><span>
Simplify: </span><span><span><span>4x - </span><span>7 </span></span>= <span><span>5x</span> + 1</span></span><span><span><span>4x</span> − 7</span>= <span><span>5x </span>+ 1</span></span>
Step 2: Subtract 5x from both sides.<span><span><span><span>4x</span> − 7</span> − <span>5x </span></span>= <span><span><span>5x </span>+ 1</span> −<span> 5x</span></span></span><span><span><span>− x </span>− 7 </span>=1 </span>
Step 3: Add 7 to both sides.<span><span><span><span>−x </span>− 7</span> + 7</span>=<span> 1+7</span></span><span><span>−x</span>=8</span>
Step 4: Divide both sides by -1.<span><span><span>‌<span><span>−x/</span><span>−1 </span></span></span>‌</span>=<span><span>‌<span> 8/<span>−1</span></span></span>‌</span></span><span>x=<span> −8</span></span>
Answer:<span>x= <span>−<span>8
hope this helps :)</span></span></span>

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2 years ago