Answer:
5.71 x 10^13 C.
Explanation:
We are given the following parameters or data or information and these data are going to help us in solving this particular Question or problem effectively and efficiently;
=> mass of Earth = 5.98 × 10^ 24kg, mass of Moon = 7.35 × 10^22 kg and the radius of orbit = 3.84 × 10^8m.
Recall that H =( G × m1 × m2) / r^2. where m1 and m2 are the masses of the two bodies amd r is the radius.
We will be making use of the formula below:
the value of Q to maintain the present orbit = √ { ( 7.35 × 10^22 ) × (5.98 × 10^24) × 4 × π × V.
the value of Q to maintain the present orbit = 5.71 x 10^13 C.
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It is primary because it is the official process of methodically collecting information about a certain topic in a specific time period
The answer is eighteen thousand pounds of tea
