Matrix A has order 4 x 8, Matrix B has order 4 x 16.

1 answer:

3 0

Matrix A order is 4x8.
Matrix B order is 4x16.
AB cannot result because an (m x n) can only be multiplied by an (n x p) matrix and orders don't match the requirements.
BA has the same negative result.

You might be interested in

A box is in the shape of an equilateral triangular prism. if the box is to be covered with paper on its lateral sides, how many

Zarrin [17]

The total surface area of the triangular prism that has a height of h and the side length of a is given below.

$\rm a(\dfrac{\sqrt3}{2} \ a + 3h)$

<h3>What is a triangular prism?</h3>

A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.

A box is in the shape of an equilateral triangular prism.

If the box is to be covered with paper on its lateral sides.

Let a be the side length of the equilateral triangle and h be the height of the prism.

Then the surface area of the triangular prism will be

Surface area = 2 × area of triangle + 3 × area of the rectangle

The area of the triangle will be

$\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}$

The area of the rectangle will be

$\rm Area \ of \ rectangle = a \ h$

Then the total surface area will be

$\rm Surface\ area = 2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area = a(\dfrac{\sqrt3}{2} \ a + 3h)$

More about the triangular prism link is given below.

brainly.com/question/21308574

7 0

2 years ago

A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

stepladder [879]

Answer: 1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀ where

a is the acceleration (in this case it is gravity)
v₀ is the initial velocity
h₀ is the initial height

Given:

a = -9.81 (if it wasn't given in your textbook, you can look it up)
v₀ = 12
h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION: 0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

a=-9.81, b=12, c=3

$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\$