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andreyandreev [35.5K]
2 years ago
5

if a woman in a plane waiting to parachute is 3,940m high and has a mass of 70kg,what is her gravitational potential energy (gpa

)​
Social Studies
1 answer:
LiRa [457]2 years ago
5 0

Answer:

\boxed {\boxed {\sf 2,702,840 \ Joules }}

Explanation:

The gravitational potential energy can be found using the following formula

E_p=m*g*h

Where <em>m</em>= mass, <em>g</em>= gravitational acceleration, and <em>h </em>= height.

We know the the mass of the woman is 70 kilograms and the height is 3,940 meters

If we assume this parachute is on Earth, then the gravitational acceleration is 9.8 m/s²

m= 70 \ kg \\h= 3,940 \ m \\g= 9.8 \ m/s^2

Substitute the values into the formula.

E_p= (70 \ kg) (9.8 \ m/s^2)(3,940 \ m)

Multiply the first two numbers first.

E_p=686 \ kg*m/s^2 (3,940 \ m )

  • 1 kg*m/s² is equal to 1 Newton. Therefore, the first number (686 kg*m/s²) is also equal to 686 Newtons

E_p=686 \ N (3,940 \ m)

Multiply again.

E_p= 2702840 \ N*m

  • 1 Newton meter is equal to 1 Joule. So, our answer of 2702840 N*m is equal to 2702840 J

E_p=2702840 \ J

The potential energy of the women is<u> 2,702,840 Joules </u>

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