Question

if a woman in a plane waiting to parachute is 3,940m high and has a mass of 70kg,what is her gravitational potential energy (gpa)​

Answer 1

Answer:

$\boxed {\boxed {\sf 2,702,840 \ Joules }}$

Explanation:

The gravitational potential energy can be found using the following formula

$E_p=m*g*h$

Where m= mass, g= gravitational acceleration, and h = height.

We know the the mass of the woman is 70 kilograms and the height is 3,940 meters

If we assume this parachute is on Earth, then the gravitational acceleration is 9.8 m/s²

$m= 70 \ kg \\h= 3,940 \ m \\g= 9.8 \ m/s^2$

Substitute the values into the formula.

$E_p= (70 \ kg) (9.8 \ m/s^2)(3,940 \ m)$

Multiply the first two numbers first.

$E_p=686 \ kg*m/s^2 (3,940 \ m )$

• 1 kg*m/s² is equal to 1 Newton. Therefore, the first number (686 kg*m/s²) is also equal to 686 Newtons

$E_p=686 \ N (3,940 \ m)$

Multiply again.

$E_p= 2702840 \ N*m$

• 1 Newton meter is equal to 1 Joule. So, our answer of 2702840 N*m is equal to 2702840 J

$E_p=2702840 \ J$

The potential energy of the women is 2,702,840 Joules