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Mama L [17]
3 years ago
10

A special filter can process 34 gallon of liquid in 25 minutes. If the filter processes a liquid at a constant rate, what is the

rate in gallons per hour that the filter processes the liquid?
Give your answer in fractional form.
Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0

Answer:

1.36

Step-by-step explanation:

34/25=1.36 wait nvm I messed up

Vanyuwa [196]3 years ago
7 0
1.36 I think I am not chere
You might be interested in
PLEASE HELP PLEASEEEEE
gulaghasi [49]

Answer:

Answer:

5.46π cm³

Step-by-step explanation:

Volume of sphere= 4/3πr³

= 4/3×π×(1.6)³ cm³

=5.46π cm³

hope this helped you!

4 0
3 years ago
Help- and also show the work please-
svetlana [45]

A fraction is a way to describe a part of a whole.  The correct option is C.

<h3>What is a Fraction?</h3>

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

A proper fraction is a fraction whose numerator is smaller than the denominator. When a proper fraction is raised to a positive exponent greater than 1, then the product decreases but does not reach 0.

Hence, the correct option is C.

Learn more about Fraction:

brainly.com/question/1301963

#SPJ1

8 0
2 years ago
Ryan can text 22 words in 4 minutes. At this rate, how many words could he text in 12 minutes? Fill out the table of equivalent
aleksandrvk [35]
The answer would be 66
Explanation: first you have to divide the minutes so 12 divided by 4 equals 3 so you would take the three and multiply that by 22. So 22x3 is equal to 66
3 0
3 years ago
Vidhur is thinking of a three digit number.
antoniya [11.8K]
I think there are 200 numbers as if we do 1000-800 (10-8 as there are only 2 numbers that can be divided by 5 exactly up to 10) that leaves 200 numbers
3 0
3 years ago
Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
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