A donut shop bakes 4 dozen donuts every 18 minutes. Find the average rate to the nearest hundredth.

1 answer:

7 0

Answer: 2.67 donut/minute
To find the average rate, you need to know the donut production and the time needed. In this question, the unit used is dozen donut and minutes. Assuming you want the rate to have donut/minute then the calculation would be:

Rate:
4x12 donuts / 18 minute
48 donut /18 minute
2.67 donut/minute

You might be interested in

If the clothing maker bought 500 m2 of this fabric, how much money did he lose? Use 1tepiz=0.625dollar and 0.9144m=1yard.

Ivanshal [37]

1 yard^2 = 0.8361m^2.?

<span>The solution to the problem is as follows:

So he spent (.625 x 400) = $250.00 per m^2. </span>
He paid out (500 x 250) = $125,000 on the deal.
He received (500 / 0.8361) = 598.014592 yard^2 of fabric.
That would have cost (598.014592 x 120) = $71,761.75 locally.
He lost (125,000 - 71,761.75) = $53,238.25 on the deal.

<span>You can rework with the incorrect conversion factor.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>

7 0

3 years ago

Read 2 more answers

75% of the Spanish Club is boys . If there are 36 members in the Spanish club, how many are girls?

7nadin3 [17]

48 i know because i used a calculator

3 0

3 years ago

Please help I can’t figure it out

Lynna [10]

Answer:

149.71

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$