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sukhopar [10]
3 years ago
15

A car wash detailed 256 cars in 8 hours. At what rate did the car wash detail

Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
32 cars per hour. If you do 256 divided by 8 you get 32.

Hope this helped!
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I need help with this q8
lbvjy [14]

Answer:

y=5x

Step-by-step explanation:

From (2,10) you rise 25 in the y direction and run 5 in the x direction to get to the next known point (7,35).

Thus, the slope is y=25/5x AKA y=5x

8 0
3 years ago
I need help with this. I've tried to type out this problem, but it comes out wrong, so I uploaded a picture:
tatuchka [14]

answer: 6.4

work:

Solve the problem.

Let's start by solving the numerator,

(5 + 3)² <em>step one: add 5 + 3 </em>

(8)² <em>step two: simplify 8²</em>

64

now, let's simplify our denominator

1 + 2⁵ - 23 <em>step one: simplify 2⁵.</em>

1 + 32 - 23 <em>step two: add 1 + 32.</em>

33 - 23 <em>step three: subtract 33 - 23</em>

10.

now, put the numerator back over the denominator.

64/10

let's simplify by dividing, we get 6.4.

<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>


4 0
3 years ago
If the cost of a raffle ticket is $2, which of the following expressions could be used to represent the cost of m tickets? 2m 2
Bingel [31]
It would be 2m because each ticket is 2 dollars and then you have to multiply it by the number of tickets you are buying M
6 0
3 years ago
Please answer quickly! will give brainliest!
Y_Kistochka [10]

Answer:

12 cows and 5 chickens

8 0
2 years ago
Keiko has seven colors of lanyard. She uses three different colors to make a keychain. How many different combinations can she c
AleksAgata [21]
Combination = doesn't matter what order
Permutation = order matters

There are <u>two</u> methods to work out combinations.

Method 1 List out possibilities
123 124 125 126 127 134 135 136 137 145 146 147 156 157 167
234 235 236 237 245 246 247 256 257 267
345 346 347 356 357 367
456 457 467
567

For a total of 35 combinations.

Method 2 Use a formula.
It's a rather complicated one, so only use it if you have a lot of possibilities.

\frac{n!}{r!(n-r)!} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!*4!} = \frac{7*6*5*4*3*2*1}{3*2*1*4*3*2*1} = \frac{7*6*5}{3*2*1}=\frac{210}6=35

(n is the number of choices, r is the amount you choose, and ! is a function that multiplies together all numbers down to 1)


7 0
3 years ago
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