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spayn [35]
3 years ago
7

Kallisto built a rectangular sign that measured 2 and 3/4. The width is 1 and 1/4 shorter than the length. To find the area, mul

tiply the length and width. What is the area in square feet write an equation to solve it
Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

<em>l</em> = 1 5/16

w = 1/16

A = 21/16 x 1/16 = 21/256

Step-by-step explanation:

Perimeter = 11/4

<em>l</em> = length

w = <em>l</em> - 5/4

2<em>l</em> + 2(<em>l</em> - 5/4) = 11/4

2<em>l</em> + 2<em>l</em> - -5/2 = 1/4

multiply each side by 4

8<em>l</em> + 8<em>l </em>- 10 = 11<em> </em>

16<em>l</em> = 21

<em>l</em> = 21/16 or 1 5/16

width = 21/16 - 20/16 = 1/16

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Answer:

The distance formula is: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

Given:

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(x_1,y_1)\ and\ (x_2,y_2)

Now, let the points be A(x_1,y_1)\ and\ B(x_2,y_2) and let 'd' be the distance between the two points.

Now, join the points A and B to make a line segment AB.

Also, draw a right angled triangle ABC right angled at point C. Point C is is the intersection of horizontal and vertical lines drawn from points A and B respectively as shown in the figure below.

From the triangle ABC, we observe that:

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Now, we use Pythagoras theorem to find 'd'. This gives,

AB^2=AC^2+BC^2\\\\d^2=(x_2-x_1)^2+(y_2-y_1)^2

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\sqrt{d^2}=\pm\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Ignoring the negative result as distance can never be negative.

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d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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