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spayn [35]
3 years ago
7

Kallisto built a rectangular sign that measured 2 and 3/4. The width is 1 and 1/4 shorter than the length. To find the area, mul

tiply the length and width. What is the area in square feet write an equation to solve it
Mathematics
1 answer:
prisoha [69]3 years ago
8 0

Answer:

<em>l</em> = 1 5/16

w = 1/16

A = 21/16 x 1/16 = 21/256

Step-by-step explanation:

Perimeter = 11/4

<em>l</em> = length

w = <em>l</em> - 5/4

2<em>l</em> + 2(<em>l</em> - 5/4) = 11/4

2<em>l</em> + 2<em>l</em> - -5/2 = 1/4

multiply each side by 4

8<em>l</em> + 8<em>l </em>- 10 = 11<em> </em>

16<em>l</em> = 21

<em>l</em> = 21/16 or 1 5/16

width = 21/16 - 20/16 = 1/16

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Can someone answer this please and thank you
musickatia [10]

Answer:

See below.

Step-by-step explanation:

x+3/9=5/9

  -3/9  -3/9

x=2/9

--------------

11+x=50

-11     -11

x=39

-------------

2/9+x=8/9

-2/9     -2/9

x=6/9 or 2/3

-hope it helps

7 0
2 years ago
john currently has enough money to buy 45 books. If the cost of each book was 10 cents less.john could buy 5 more books. How muc
SVEN [57.7K]
Let the cost of one book= x cents
Let the money john have= y cents

According to the question,

45x=y                                               ...eq(1)
(45+5)(x-5)=y                                  
50(x-5)=y                                         
50x-250=y                                        ...eq(2)

On subtracting (1) from (2).
(50x-250)-45x=y-y
5x-250=0
x=250/5
x=50

Thus, cost of each book is 50 cents and john has 2250 cents.

Hope it helps.
Don't feel shy in saying thx if it helps.


4 0
3 years ago
Solve x+2/x-4&lt;0<br><br> A)–4 &lt; x &lt; –2<br> B)–2 &lt; x &lt; 4<br> C)–2 &lt; x &lt; –4
Gelneren [198K]

Domain:\ x\neq-2\\\\\dfrac{x+2}{x-4}

Other method:

\dfrac{x+2}{x-4}

zeros of numerator and denominator are x = -2 and x = 4.

Look at the second picture.

for x < -2 → x + 2 < 0 and x - 4 < 0

therefore \dfrac{x + 2}{x - 4}=\dfrac{(-)}{(-)}>0

for -2 < x < 4 → x + 2 > 0 and x - 4 < 0

therefore \dfrac{x+2}{x-4}=\dfrac{(+)}{(-)} < 0

for x > 4 → x + 2 > 0 and x - 4 > 0

therefore \dfrac{x+2}{x-4}=\dfrac{(+)}{(+)} > 0

<h3>Answer: B) -2 < x < 4</h3>

4 0
3 years ago
Wright a variable expression for the word phrase, "the product of a number z and 7" A: 7 - z
drek231 [11]
Product means to multiply so, C
3 0
3 years ago
Winter temperatures tend to be cold in the city of Johnstown. The table of values represents the temperature of Johnstown during
trapecia [35]

Answer:

Part A Part B Part C explained

Step-by-step explanation:

PART A: Extrema: relative minimums (4,-2) and maybe (7,-3) (uncertain because it’s an endpoint), relative maximums (6,0) and maybe (1,6) (uncertain because it’s an endpoint)

Zeros: (6,0), somewhere between t = 3 and t = 4 since the graph changes from positive to negative, and somewhere possibly between t = 6 and t = 7 unless the graph hits (6,0) and stays negative.

End behavior: We can guess that as x approaches infinity, the functions approaches negative infinity, and as x approaches negative infinity, the function approaches infinity.

Intervals of increase and decrease: Increasing on (4, 6), decreasing on (1, 4) and (6, 7)

PART B: The relative minimums indicate that the two lowest temperatures occurred on day 4 at -2°F and day 7 at -3°F. The relative maximums indicate that the weekly highs were day 1 at 6°F and day 6 at 0°F.

The zeros of the function represent when the temperature in Johnstown was 0°F. This happened sometime between days 3 and 4 and on day 6.

In the context of the problem, it doesn’t make sense to go an infinite number of degrees below zero. And, the end behavior is ignored because of the restricted range.

The intervals of increase indicate when the temperature is rising, and the intervals of decrease indicate when the temperature is dropping. The intervals where the values are positive indicate when the temperature is above 0°F. The intervals where the values are negative indicate when the temperature is below 0°F.

PART C: The domain is restricted to the number of days the town recorded the temperature. So, the domain is [1, 7].

The range represents the range of temperatures of Johnstown over the course of one week. So, the range is [-3, 6].

6 0
3 years ago
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