So divide 20 into 3
then u do wat u do 4 the rest
If b+2(a+1) = c, find the value of a+1
Subtract b from both sides: b+2(a+1) - b = c - b
2(a+1) = c - b
Divide both sides by 2:
a+1 = (c - b) /2
Answer:
x² + 6x - 5x – 30=(x-5)(x+6)
Step-by-step explanation:
x² + 6x - 5x – 30=x²+x-30
delta=1-4(-30)=1+120=121=11²
Sqrt(delta)=11
The roots are:
x1,2=(-1 +- 11)/2
Thus we get
x1=(-1+11)/2=10/2=5
x2=(-1-11)/2=-12/2=-6
Finally:
x² + 6x - 5x – 30=(x-5)(x+6)