So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:
This is a decimal therefore <em>not</em> an integer.
B:
Again a decimal, therefore <em>not </em>an integer.
C:
This is a whole number, so it <em>is </em>an integer.
D:
Decimal, therefore <em>not </em>an integer
E:
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.
I would but I’m stuck on this problem too
If you would like to solve <span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4), you can do this using the following steps:
</span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4) = 8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4 = 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6
</span>
The correct result would be 8r^6s^3 – 5r^5s^4 + r^4s^5<span> + 5r^3s^6.</span>
The mistake is that that is an equilateral triangle with the same answer for each side which is 6 so AC=6 BC=6 BA=6 all sides equal 6