The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).
<h3>How to find an approximate solution of a one-variable equation</h3>
The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.
x = (4 + 5) / 2
x = 4.5
f(4.5) = 4.5² - 5 · 4.5 + 1
f(4.5) = - 5 / 4
g(4.5) = 2 / (4.5 - 1)
g(4.5) = 4 / 7
The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:
x = (4.5 + 5) / 2
x = 4.75
f(4.75) = 4.75² - 5 · 4.75 + 1
f(4.75) = - 3 / 16
g(4.75) = 2 / (4.75 - 1)
g(4.75) = 8 / 15
The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:
x = (4.75 + 5) / 2
x = 4.875
f(4.875) = 4.875² - 5 · 4.875 + 1
f(4.875) = 25 / 64
g(4.875) = 2 / (4.875 - 1)
g(4.875) = 16 / 31
The <em>approximate</em> solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).
To learn more on successive approximations: brainly.com/question/27191494
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Given a table, with an input (x) and output (y) , you could actually use the slope formula to get the rate of change because slope is the same thing as rate of change. If you recall, the slope formula is (y2-y1)÷(x2-x1)
Just pick two points from the chart and plug them in and that is your rate of change
Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
Answer:
the answer is 5/8
Step-by-step explanation:
