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3 years ago

How can I compare these scores?

Mathematics

2 answers:

ra1l [238]3 years ago

8 0

You can convert each as a percentage or convert them all out of 5.

NISA [10]3 years ago

6 0

4/20 simplified is 1/5.

1/5 in percent is 20%

So you have 20%, 25%, and 20%

In decimal, you have:

.20, .25, .20

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An eighth-grade student claims she can prove that subtraction of integers is commutative. She points out that if a and b are int

irina [24]

That is right. Just like a * b = b * a

7 0

3 years ago

The given table and equation represent the cost for carnival rides.

lozanna [386]

Answer:

The ordered pairs that are presented are (7, 99.5) and (3, 51.5)

Step-by-step explanation:

We are given the cost function of the carnival rides as

$c=15.5+12f$

which is a typical linear expression of the form $y=ax+b$ where here $y=c$ , $f=x$ , $a=12$ and $b=15.5$ . To check if an ordered pair i.e. a point $(x,y)$ , is represented by the table we can simply plug in the equivalent $x$ value in the equation, and check if the result matches the $y$ value.

So, lets assume that all points are given correctly and they are as follow:

$A. (7, 99.5)\\B. (75.5, 5)\\C. (3, 51.5)\\D. (123.5, 9)$

Now let us check each point with our function as follow:

Point A

$(7,99.5)\\\\c=15.5+12(7)\\c=15.5+84\\c=99.5$

So point A is part of the equation.

Point B

$(75.5,5)\\c=15.5+12(75.5)\\c=15.5+906\\c=921.5$

So point B is NOT part of the equation.

Point C

$(3,51.5)\\c=15.5+12(3)\\c=15.5+36\\c=51.5$

So point C is part of the equation.

Point D

$(123.5,9)\\c=15.5+12(123.5)\\c=15.5+1482\\c=1497.5$

So point D is NOT part of the equation.

8 0

4 years ago

Read 2 more answers

Average sales for an online textbook distributor were $67.63 per customer per purchase. Assume the sales are normally distribute

Fynjy0 [20]

Answer:

(a)P(x>85.55)=0.02275

(b) $P(x$

Step-by-step explanation:

We are given that

Average sales for an online textbook distributor per customer per purchase

, $\mu=$ $67.63

Standard deviation of the amount spent on textbooks, $\sigma=$ $8.96

(a) We have to find probability for a randomly selected customer spent more than $85.55 per purchase.

$P(x>85.55)=P(\frac{x-\mu}{\sigma}>\frac{85.55-67.63}{8.96})$

= $P(Z>2)$

= $1-P(Z\leq 2)$

= $1-0.97725$

P(x>85.55)=0.02275

(b)We have to find probability for a randomly selected customer spent less than $76.59 per purchase

$P(x$

$P(x$

6 0

3 years ago

jose bought 8 bags of oranges.each bag weighed 12 ounces. there are 16 ounces in a pound.how many pounds of oranges did jose buy

notsponge [240]

Hello!

First you have to find the amount of ounces the oranges weigh

To find this you multiply the amount of oranges by the how much they weigh

12 * 8 = 96

Divide this by the amount of ounces is in a pound

96 / 16 = 6

The answer is 6 pounds

Hope this helps!

3 0

3 years ago

Please help me out....

grandymaker [24]

Answer:

It is the first one, so

7u + 5v

8 0

3 years ago

Read 2 more answers