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Nitella [24]
2 years ago
14

Can you please help me with this problem ​

Mathematics
1 answer:
padilas [110]2 years ago
6 0

Answer:

Yes

Step-by-step explanation:

One of the ways you can prove if a parallelogram is a parallelogram is if the sides in the shape are congruent and that's exactly what this proof is showing

Hope this image helps

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\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
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\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
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3 years ago
I need help with this problem and would really appreiciate a short explanation too.<br> 15 PTS
inysia [295]

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^

1= 7 +b

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---------------

-6=B

b is 6. now place it into the equation, replacing the x and y values back.

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