ΔQTR and ΔSTP are similar triangles. The corresponding sides of similar triangles are the same length.
TR = PT
TS = QT
Input the algebraic expression to make an equation system
PT = TR
y = 2x - 1 <em>(first equation)</em>
TS = QT
6x + 13 = 5y
6x - 5y = -13 <span><em>(second equation)</em>
</span>Using subtitution method, subtitute y with 2x - 1 from first equation into the second equation, to find the value of x
6x - 5y = -13
6x - 5(2x - 1) = 13
6x - 10x + 5 = 13
-4x + 5 = 13
-4x = 13 - 5
-4x = 8
x = 8/-4
x = -2
Find y with subtituting x with -2 in the first equation
y = 2x - 1
y = 2(-2) - 1
y = -4 - 1
y = -5
Answer:
x = -2
y = -5
The given trinomial can be factored using the factorization method.
x² - 2x - 24
The middle term should be written is such a way that the sum of two terms is equal to the middle one and their product should be equal to the product of first and third term. So the above expression can be written as
= x² -6x + 4x - 24
= x(x-6) + 4(x-6)
= (x-6)(x+4)
Thus, (x-6)(x+4) is the factored form of the polynomial.
So the correct answer is option B
If you would like to write x = 1/3 * y in general form, you can do this using the following steps:
The general form of the equation is: ax + by + c = 0.
x = 1/3 * y
x - 1/3 * y = 0
The correct result would be x - 1/3 * y = 0.
Step-by-step explanation:
there must be something wrong with your text.
what we can see is
3.8 × 105
and
1.9 × 1022
the true answer for these values has nothing to do with the 4 answer options.
maybe you meant
1.9 × 10.5 ?
because that answer would be 20.
but first working with the presented numbers :
3.8 × 105 = 399
1.9 × 1022 = 1941.8
so, the second number is actually much bigger than the first number.
but if it is
1.9 × 10.5 = 19.95
that works.
and we can either use the calculator to calculate
399 / 19.95 = 20
or we can simply look at the factor changes of the multiplication terms.
3.8 = 1.9 × 2
105 = 10.5 × 10
so, the multiplication product of the two larger numbers is then 2×10=20 times larger than the product of the 2 smaller numbers.
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