The quantity of each type of seats sold are as follows:
- Movie and a dinner seat = 200
According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.
That is, x = 4y
Also, total seats
= (x) + (y) + (z) = 3000...….............eqn(1)
Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.
- 20x + 35y + 15z = 53000...........eqn(2)
By substituting 4y for x in equations 1 and 2; we have;
<em>5y + z = 3000</em>..…........eqn(3) and
<em>115y + 15z = 53000</em>.........eqn(4)
By solving equations 3 and 4 simultaneously; we have;
y = 200 and z = 2000
and since x = 4y
x = 800
The quantity of each type of seats sold is as follows:
- Movie and a dinner seat = 200
Read more:
brainly.com/question/12413726
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]
Answer:
(x-4)(x-4)(x+2)
Step-by-step explanation:
Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives
x^2-2x-8
Q(x) = P(x)/d(x)
x^3-6x^2+32/x- 4 = x^2-2x-8
Factorizing the quotient
x^2-2x-8
x^2-4x+2x-8
x(x-4)+2(x-4)
(x-4)(x+2)
Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)
