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Maru [420]
3 years ago
8

A radio station plays a winning song once per hour at a randomly selected time (in minutes). During an announcer’s four-hour sho

w, how many different arrangements of winning times could occur if a) repetition of times during each hour is permitted? b) repetition of times during each hour is not permitted?
Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Answer:nrkrdjdjddjdjdjjdjdjdjdjdjd

Step-by-step explanation:

Hdhdhdhdhdhd

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it has to be irrational

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Use the quotient rule to prove that the power rule is valid for negative whole number powers.​
-BARSIC- [3]

Answer:

ddx(x−m)=−mx−m−1

That is, ddx(x−m)=−mx−m−1. where m is a positive integer.

6 0
2 years ago
What is the answer?
kumpel [21]
$41.83

7.25% as a decimal is 0.0725.

multiply 39.00 by 0.0725 to get the tax.

the tax is $2.83 and the product is $39.00. that added together is $41.83.
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3 years ago
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BRAINLIEST TO FIRST PERSON!<br><br><br> Which one is the correct answer?
Tamiku [17]

Answer:

Option 3 is not conclude or whatever that means lol, i just know it

Step-by-step explanation:

3 0
3 years ago
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
masha68 [24]

Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

We note that the volume of a cone = \dfrac{1}{3} \cdot A_b \cdot h

Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

4·h = 150

h = 150/4 = 37.5 cm

The height of the cone = 37.5 cm

4) The storage area at the back corner  with four sides = 100 m²

The storage area at the back of the building with three sides = 98 m²

Given that the available riling = 28 m, we have;

For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

5 0
4 years ago
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