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Kisachek [45]
3 years ago
14

The length of a rectangle is represented by (2x2−5x+5)cm and the width is represented by (x2+4x−3)cm. What is the representation

of the perimeter
Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Answer: 6x^2-2x+4

Step-by-step explanation:

Given

The length of a rectangle is given by

l=2x^2-5x+5

and the breadth is given by

w=x^2+4x-3

Perimeter is the sum of the sides of rectangle

\therefore \text{Perimeter P= }2(2x^2-5x+5+x^2+4x-3)\\\Rightarrow P=2(3x^2-5x+4x+5-3)\\\Rightarrow P=2(3x^2-x+2)\\\Rightarrow P=6x^2-2x+4

Thus, the perimeter is given by 6x^2-2x+4.

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A falcon to fly 322 km/h how many meters per hour on the falcon fly
boyakko [2]
1 km = 1,000 m....so 322km = 322,000 m
so the falcon can fly 322,000 m per hr
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3 years ago
What is the constant of variation, k, of the line y = kx through (3,18) and (5,30)?
Fudgin [204]
Y is 18 so 18=3k
k=18/3
k=6 for (3,18)
for (5,30)let's see
y=30
30=5k
k=30/5
k=6
5 0
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What is the value of x in this equation -6x =72
Svetradugi [14.3K]
The value of x in that equation is -12
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3 years ago
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Select all expressions that are equivalent to (2n+6)(n+3)
eduard

Answer:

(2n+6)(n+3)=

(2*n+2*3)(n+3)=

2(n+3)(n+3)=.....(1)

2(n+3)^2=....(2)

2(n^2+2*n*3+3^2) =

2(n^2+6n+9)=....(3)

2n^2+2*6n+2*9=

2n^2+12n+18.... (4)

6 0
3 years ago
Bob Nale is the owner of Nale's Texaco GasTown. Bob would like to estimate the mean number of litres (L) of gasoline sold to his
Fudgin [204]

Answer:

a

  The point estimate of the population mean is  \= x  =  56

b

  The 80% confidence level is  50.57 <  \mu  < 61.43

c

  There is  80% confidence that the true population mean lies within the confidence interval.

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  18

   The  standard deviation is  \sigma  =  18 \ L

   The  sample mean is  \= x  =  56

Generally the point estimate of the population mean is equivalent to the sample mean whose value is  \= x  =  56

Given that the confidence interval is 80% then the level of significance is mathematically represented as

      \alpha  =  100 -  80

      \alpha =  20 \%

      \alpha = 0.20

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table

 The  value is   Z_{\frac{ \alpha }{2} } =  1.28

 Generally the margin of error is mathematically evaluated as

          E =  Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }

=>       E =  1.28 * \frac{18 }{\sqrt{18} }

=>       E =  5.43

     Generally the 80% confidence interval is mathematically represented as

    \= x  - E  <  \mu  < \= x  + E

=>    56  - 5.43  <  \mu  < 56  + 5.43

=>   50.57 <  \mu  < 61.43

The  interpretation is that there is  80% confidence that the true population mean lies within the limit

3 0
3 years ago
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