In a bag of snack mix:
n = nuts d = dried fruit
n = 744g d = ???g
Ratio Nuts/Dried fruit = 12/13
This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits
If 744 is 12 parts then 744/12 is 1 part
744/12 = 62
1 part = 62g
there are 13 parts of dried fruit
13 x 62 = 806
744g of nuts + 806g of dreid fruit = 1550g
Answer: A batch of snack mix weigh 1550g, or 1.55kg
hope it helps :)
Answer:
are there any numbers?
Step-by-step explanation:
I solved it on your other posting of it. x = 12
All of the steps are there
Answer:
for 3, 4 or both?
4. is probably zero
Step-by-step explanation:
Wait is 4 a question?
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
