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Kay [80]
2 years ago
15

Guys please help me this is due tonight thanks

Mathematics
1 answer:
elena-s [515]2 years ago
4 0

Answer:

the student in question bought 3 large notebooks and 3 small notebooks

Step-by-step explanation:

the easiest way to explain how to do this is by recognizing that the student bought $54 worth of notebooks- which is not divisible by 10 easily. that means, we should subtract 8 from 54 until we get a number that IS divisible

54 - 8 = 46 (one small notebook)

46 - 8 = 38 (two small notebooks)

3 8 - 8 = 30 (three small notebooks)

then, divide 30 by 10 to see how many large notebook the student bought.

30/10 = 3

the student in question bought 3 large notebooks and 3 small notebooks

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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

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Time (t in years) = 0.5 years

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Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
3 years ago
The table shows the probabilities of winning or losing when the team is playing away
Lesechka [4]

Answer:a

Step-by-step explanation:

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2 years ago
Consider all numbers consisting of four different digits all between 1 and 9 . How many of these are odd
Slav-nsk [51]

Answer:

1680

Step-by-step explanation:

Considering repeatition is not allowed.

We can  use permutation to reach to the required answer.

Consider four digits to be placed in four boxes. Now for the number to be odd, unit digit must be odd. Therefore, unit digit can only be filled by 1, 3, 5,7, or 9. That is 5 ways. Now, other three boxes can be filled with 8, 7 and 6 ways respectively.

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3 years ago
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