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Kay [80]
3 years ago
15

Guys please help me this is due tonight thanks

Mathematics
1 answer:
elena-s [515]3 years ago
4 0

Answer:

the student in question bought 3 large notebooks and 3 small notebooks

Step-by-step explanation:

the easiest way to explain how to do this is by recognizing that the student bought $54 worth of notebooks- which is not divisible by 10 easily. that means, we should subtract 8 from 54 until we get a number that IS divisible

54 - 8 = 46 (one small notebook)

46 - 8 = 38 (two small notebooks)

3 8 - 8 = 30 (three small notebooks)

then, divide 30 by 10 to see how many large notebook the student bought.

30/10 = 3

the student in question bought 3 large notebooks and 3 small notebooks

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6 * 7 = 42 so then you take and divide

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Parking in a student lot costs $2 for the first half hour and $1.75 for each hour thereafter. A partial hour is charged the same
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An easier way to think of this problem is just keep adding for each additional hour: 


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To illustrate the effects of driving under the influence of alcohol, a police officer brought a DUI simulator to a local high sc
nexus9112 [7]

Answer:

Check the explanation

Step-by-step explanation:

Here we have to first of all carry out dependent sample t test. consequently wore goggles first was selected at random for the reason that the reaction time in an emergency taken with goggles would be greater than the amount of reaction time in an emergency taken with not so weakened vision. So that we will get the positive differences d = impaired - normal

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To find 95% confidence interval first we need to find sample mean and sample sd for difference d = impaired minus normal.

We can find it using excel that is in the first attached image below,

Therefore sample mean ( \bar{X}_{d} ) = 0.98

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Kindly check the attached image below.

Therefore we are 95% confident that mean difference in braking time with impaired vision and normal vision is between ( 0.6888 , 1.2712)

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There is significant evidence that  there is a difference in braking time with impaired vision and normal vision at 95% confidence level .

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