All categories

3 years ago

What is the answer to 4x-5=x-23 need step by step explanation

Mathematics

1 answer:

Grace [21]3 years ago

8 0

Answer:

x=−6

Step-by-step explanation:

4x−5=x−23

Step 1: Subtract x from both sides.

4x−5−x=x−23−x

3x−5=−23

Step 2: Add 5 to both sides.

3x−5+5=−23+5

3x=−18

Step 3: Divide both sides by 3.

3x /3=-18/3

x=-6

You might be interested in

Evaluate C(8,3) C(8,3)=

Arlecino [84]

8 choose 3 = 8!/(3!*(8-3)!) = 8*7*6/(3*2) = 56

7 0

4 years ago

If x>7, then |x|>7. |y|>7, so y=7 Valid or invalid?

Alex

$\text{if }x>7\text{, then }|x|>7$ is a valid argument

$|y|>7\text{, so }y=7$ is not a valid argument

For the first argument: $\text{if }x>7\text{, then }|x|>7$

From the definition of absolute value function

$|x|=x$ if $x\ge0$

That is every positive number is its own absolute value. Since

$x>7\implies x\ge0$ ,

we can argue that

$x>7\implies |x|>7$

so the first argument is valid

For the second argument: $|y|>7\text{, so }y=7$

From the definition of absolute value function

$|y|:=\left \{ {y\text{ if }y\ge0}\atop{-y\text{ if }y$

This means that

$|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{-y>7\text{ if }y$

$|y|>7:=\left \{ {y>7\text{ if }y\ge0}\atop{y$

no part of the definition allow for the option $y=7$ . So the second argument is not valid.

Learn more here: brainly.com/question/11897796

7 0

3 years ago

(Please someone help me!) (No links!) What do I do!

Eddi Din [679]

Answer:

a: 30 b: -7 c. -11

Step-by-step explanation:

a. (3)(-5)(-2)

Which is 3x-5x-2:

3x-5 is -15

-15x-2=30

b. -5-2=-7

c. 3(-2)+-5

-6+-5=-11

Hence, the correct answers are 30,-7,-11

6 0

3 years ago

Luanne flips a coin and rolls a six-sided number cube. What is the probability that the coin will land on heads and the number c

klasskru [66]

Luanne flips a coin and rolls a six-sided number cube. What is the probability that the coin will land on heads and the number cube will land on three?

Answer: 1/12

3 0

3 years ago

Read 2 more answers

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

worty [1.4K]

Hello,

h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
h(1)=f'(1)*g(1)+(f(1)*g'(1)=-4*3+4*(-3)=-24
Answer B

7 0

4 years ago