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3 years ago

Find the midpoint of the segment with the following endpoints. (7, -2) (1, -10)

Mathematics

2 answers:

dem82 [27]3 years ago

8 0

Answer:

Step-by-step explanation:

The formula of a midpoint of the segment AB:

$M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

We have A(7, -2) and B(1, -10). Substitute:

$M_{AB}\left(\dfrac{7+1}{2};\ \dfrac{-2+(-10)}{2}\right)\\\\M_{AB}\left(\dfrac{8}{2};\ \dfrac{-12}{2}\right)\\\\M_{AB}(4;\ -6)$

Alexus [3.1K]3 years ago

6 0

Midpoint = average of x and y
(7+1)/2 x value = 4
(-2+ -10)/2 y value = -6
Midpoint (4, -6)

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Dhruv is at a car dealership. He is going to randomly select a vehicle to test drive. There are

andrew-mc [135]

Answer:

P(compact cars) = 4/25

Step-by-step explanation:

We know that there are 13 trucks, 8 vans, and 4 compact cars.

Let P denotes the probability of an event

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Number of favorable events = number of compact cars = 4

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2 years ago

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3 years ago

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Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc

siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be $x.$

So, 54 is equivalent to 36.

Thus, 17 is equivalent to $x.$

$\frac{54}{36} =\frac{17}{x}$

By cross multiplying we get:

$54x=612$

Dividing both sides by 54 we get:

$x=11.33\ inches.$

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= $54\times 36:17\times 11.33$

= $1944:192.61$

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

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3 years ago

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Suppose c was a total membership cost for m the two equations that model c are c=30m+50 an c=20m+100

Maksim231197 [3]

Answer:

5 months

Step-by-step explanation:

Given

$c = 30m + 50$

$c = 20m + 100$

Required [Missing from the question]

At what month will the cost be equal

To do this, we equate both expressions

$c = c$

This gives:

$30m + 50 = 20m + 100$

Collect like terms

$30m - 20m = 100 - 50$

$10m = 50\\$

Solve for m

$m = \frac{50}{10}$

$m = 5$

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3 years ago

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Lady_Fox [76]

Answer: The figure drawn by Alan is a rhombus.

Step-by-step explanation:

Given: Allan drew a polygon with 4 sides and 4 angles with two properties:-

All four sides are equal.
None of the angles are right angles.

We know that only a rhombus is a flat shape with 4 equal straight sides and 4 angles .All sides have equal length. Its angles need not to be right angle.

Therefore, the figure drawn by Alan is a rhombus.

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3 years ago

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