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frez [133]
2 years ago
7

The diameter of a bicycle wheel is 20 inches. Which measurement is closest to the circumference of the wheel

Mathematics
1 answer:
algol [13]2 years ago
4 0

Answer:

62.8 inches

Step-by-step explanation:

✓We can determine the

Circumference of the wheel of the bicycle using the expression below;

Circumference= (πd) ...........eqn(1)

Where d= diameter = 20inches

If we substitute the value of " diameter" into eqn(1)

Circumference = (π × 20)

= 62.8inches

(Where π= 3.142)

Therefore, measurement that is closest to the circumference of the wheel is 62.8inches

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Solve: -2x - 5 = -3 <br> plz help me hurry
lord [1]

Answer:

x=-1

Step-by-step explanation:

-2x - 5 = -3

add 5 to both sides

-2x = 2

divide both sides by -2

x = -1

8 0
3 years ago
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Use the zero product property to find the solutions to the equation 6x^2 – 5x = 56.
frez [133]

Answer:

x = 7/2 or x = -8/3

Step-by-step explanation:

Solve for x over the real numbers:

6 x^2 - 5 x = 56

Divide both sides by 6:

x^2 - (5 x)/6 = 28/3

Add 25/144 to both sides:

x^2 - (5 x)/6 + 25/144 = 1369/144

Write the left hand side as a square:

(x - 5/12)^2 = 1369/144

Take the square root of both sides:

x - 5/12 = 37/12 or x - 5/12 = -37/12

Add 5/12 to both sides:

x = 7/2 or x - 5/12 = -37/12

Add 5/12 to both sides:

Answer:  x = 7/2 or x = -8/3

8 0
3 years ago
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Determine the lengths of the sides of the rectangle using the given area. Give answers both exactly and
Degger [83]

Answer:

Part a) Exactly values

The width of the rectangle is \frac{\sqrt{70}}{2}\ cm

The length of the rectangle is 2\sqrt{70}\ cm

Part b) Approximately values

The width of the rectangle is 4.2\ cm

The length of the rectangle is 16.7\ cm

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

A=LW

we have

L=4x\ cm\\W=x\ cm

substitute the values in the formula

A=4x(x)

A=4x^2

A=70\ cm^2

so

70=4x^2

Solve for x

Divide by 4 both sides

\frac{70}{4}=x^2

square root both sides

x=(+/-)\frac{\sqrt{70}}{2}

The solution is the positive value

x=\frac{\sqrt{70}}{2}

therefore

<em>Exactly values</em>

L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm

<em>Approximately values</em>

L=4\sqrt{70}}{2}=16.7\ cm\\\\W=\frac{\sqrt{70}}{2}=4.2\ cm

6 0
3 years ago
I NEED HELP ASAP BEFORE IT TIMES OUT!
padilas [110]
Ahh ok so split it up into two rectangles:

Rectangle one:
A=lw
A=4(12)
A=48

Rectangle two:
A=lw
A=10(2)
A=20

Add both areas up to get 68 ft squared!! :)
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2 years ago
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What is the surface area of this design?
klasskru [66]
I think it is 7200in.
3 0
3 years ago
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