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3 years ago

15

A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 8 tables is $58. The total cost to re

nt 5 chairs and 2 tables is $23. What is the cost to rent each chair and each table?

1 answer:

schepotkina [342]3 years ago

7 0

Answer:

Equations::

4c + 8t = 58

2c + 3t = 23

----------------

Modify for elimination:

4c (4c*1) + 8t (8t*1)= 58

4c (2c*2) + 6t (3t*2)= 46

---------------------

Subtract and solve for "t":

2t (8t-6t) = 12

t = $6 (cost of one table)

-----

Solve for "c":

2c + 3t = 23

2c + 18 = 23

2c = 5

c = $2.50 (cost of one chair)

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It is true that the product of two consecutive even integers are always one less than the square of their average.

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4 years ago

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Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

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$a(4)=75*0.50$

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Alternative Method

Applying the formula

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