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Snezhnost [94]
3 years ago
8

The quadratic x? - x = 2 has two solutions. What is the larger of the two solutions?

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0
I believe the 2 is the largest
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What is the slope of (2,-12), (18,15)
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

The slope of a line given two points (x_0,y_0) and (x_1,y_1) is

m=\frac{y_1-y_0}{x_1-x_0}=\frac{15-(-12)}{18-2}=\frac{27}{16}

7 0
3 years ago
PLEASE HELP WILL GIVE BRANLIEST IF CORRECT
nevsk [136]

Answer:

1,500,000,000

Step-by-step explanation:

6 0
2 years ago
Simplify 7^-5/6*7^-7/6
DochEvi [55]

So the rule with multiplying exponents of the same base is x^m*x^n=x^{m+n} . Apply this rule here:

7^{-\frac{5}{6}}*7^{-\frac{7}{6}}=7^{-\frac{5}{6}+{-\frac{7}{6}}}=7^{-\frac{12}{6}}=7^{-2}

Next, the rule with converting negative exponents into positive ones is x^{-m}=\frac{1}{x^m} . Apply this rule here:

7^{-2}=\frac{1}{7^2}=\frac{1}{49}

<u>Your final answer is 1/49.</u>

<h2>------------------------------------------------</h2>

So an additional rule when it comes to exponents is x^{\frac{m}{n}}=\sqrt[n]{x^m}

In this case, your fractional exponent, x^9/7, would be converted to \sqrt[7]{x^9} . However, I had just realized you can further expand this.

Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:

\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}

Your final answer would be x\sqrt[7]{x^2}

3 0
3 years ago
The height of the building where the wire is attached is 70 feet
Alexeev081 [22]
This is not a question...please rephrase.
3 0
3 years ago
How do I solve this
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Hello,

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8 0
3 years ago
Read 2 more answers
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