All categories

3 years ago

Can someone please help

Mathematics

1 answer:

Inga [223]3 years ago

3 0

Answer:

15 boys.

Step-by-step explanation:

A class constituting of boys and girls:

Has a total of 35 students.

The number of girls outnumber that of boys by 5.

Let the number of boys be x such that the number of girls is x + 5.

∴

x + x + 5 = 35

2x + 5 = 35

2x = 35 - 5 = 30

x = 30/2 = 15

So there are 15 boys and 35 - 15 = 20 girls.

*<em>I believe you can now solve the second question.</em>

You might be interested in

There were 166 paid admissions to a game. The price was $2 for adults and $.75 for children. The amount of data taken in was $29

JulijaS [17]

Answer:the number of adults that attended the game is 135.

the number of children that attended the game is 31

Step-by-step explanation:

Let x represent the number of adults that attended the game.

Let y represent the number of children that attended the game.

There were 166 paid admissions to a game. This means that

x + y = 166

The price was $2 for adults and $.75 for children. The amount of data taken in was $293.25. This means that

2x + 0.75y = 293.25 - - - - - - - - - - 1

Substituting x = 166 - y into equation 1, it becomes

2(166 - y) + 0.75y = 293.25

332 - 2y + 0.75y = 293.25

- 2y + 0.75y = 293.25 - 332

- 1.25y = - 38.75

y = - 38.75/- 1.25

y = 31

x = 166 - y = x = 166 - 31

x = 135

5 0

3 years ago

P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 30, p = 0.626$

$\mu = E(X) = np = 30*0.626 = 18.78$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65$

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is $P(X \leq 16 + 0.5) = P(X \leq 16.5)$ , which is the pvalue of Z when X = 16.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16.5 - 18.78}{2.65}$

$Z = -0.86$

$Z = -0.86$ has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0

2 years ago

The measure of the supplement angle is fourteen times greater than its supplement

disa [49]

Let's assume you have supplement angle
$x$
Now when you talk about multiplication you can simply say...
$14x = y$
And that will give you the answer.

6 0

2 years ago

Witch is grater 3/4 or 11/16 ??

kow [346]

<h3>Hey there! </h3><h3> $\frac{3}{4}$ → $0.75$ → $0.75$ %</h3><h3> $\frac{11}{16}$ → $0.6875$ → $0.68$ % </h3><h3>So, the one that is $GREATER$ is: $\frac{3}{4}$ because $75$ % is bigger than</h3><h3> $68$ %</h3><h3>Good luck on your assignment and enjoy your day! </h3><h3>~ $LoveYourselfFirst:)$ </h3>

5 0

2 years ago

Music lessons cost$20 pretty week how much do 6 weeks cost

joja [24]

6 weeks × 20 dollars = $120

4 0

3 years ago