Answer:
Step-by-step explanation:
sorry I tried but it is hard
The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:

<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:


Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:


Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
#SPJ1
Answer:
12. 5
11.
10
10
15. 7
14. 11
2
=
16
16
18. 3
+
11
17
3
4
co
loo
8
Step-by-step explanation:
12. 5
11.
10
10
15. 7
14. 11
2
Answer:
x ≤ 3
Step-by-step explanation:
2(4+2x) ≥ 5x+5 (by PEDMAS, expand parentheses first)
4(2) + 2x(2) ≥ 5x + 5
8 + 4x ≥ 5x + 5 (subtract 8 from each side)
4x ≥ 5x + 5 - 8
4x ≥ 5x - 3 (subtract 5x from both sides)
4x -5x ≥ - 3
-x ≥ - 3 (multiply both sides by -1, remember to flip the inequality when multiplying both sides by a negative number)
x ≤ 3