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IceJOKER [234]
3 years ago
15

The surface area of a game cube is 384 square millimeters. how long is each edge of the cube?

Mathematics
2 answers:
just olya [345]3 years ago
7 0
6a^2=384\\
a^2=64\\
a=8 \ mm
ZanzabumX [31]3 years ago
3 0
a\ \rightarrow\  the\ long\ of\ each\ edge\ of\ the\ cube\\the\ surface\ area\ of\ a\ game\ cube=384\ mm^2\\\\6a^2=384\ /:6\\\\a^2=64\ \ \ \Rightarrow\ \ \ a=8\\\\Ans.\ the\ long\ of\ each\ edge\ of\ the\ cube\ is\ 8\ mm.
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givi [52]
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2 1/2 x 2 1/4
becomes
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for fraction multiplication, just multiply numerator by numerator and denominator by denominator

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6 0
3 years ago
What is the reminder when (3x^3-2x^2+4x-3) is divided by (x^2+3x+3)
NARA [144]
(For full answer you might have to go to the comments)

Answer: 28x+30

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3x-11
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(x^2+3x+3) 3x^3-2x^2+4x-3


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-11x^2-5x-3

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5 0
3 years ago
Help<br> ================
creativ13 [48]

Answer:

Step-by-step explanation:

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6 0
3 years ago
The product of x and 7
EastWind [94]
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8 0
3 years ago
Read 2 more answers
A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho
MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0
3 years ago
Read 2 more answers
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