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attashe74 [19]
3 years ago
10

HOLY F THE I JUST ASKED OUT MY CRUSH!!!! SHE SAID YES!!! Now wha lol

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0

Answer:

how you gonna go out in a pandemic?

Step-by-step explanation:

unless you're in a place where the virus was handled properly, the understandable, have a nice day.

and uhh

communication is key to a healthy relationship

pentagon [3]3 years ago
4 0
Aye your a swagger.Just play it cool and be yourself
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BRAINLY!!!- if a=7, b=8, and c=9.2 is this a right triangle? why?
Travka [436]

Answer:

no

Step-by-step explanation:

If this were a right triangle we would assume the Pythagorean Theorem to prove it

a^{2} +b^{2} =c^{2}

7^{2} +8^{2} =9.2^{2}

this gives us

49+64=84.64

this is 143=84.64 and therefore not equal and not a right triangle

7 0
3 years ago
Alisa says it is easier to compare numbers is set A (45,760/ 1025680) than set B (492,111/ 409,867.
tankabanditka [31]
You are confused that is true
8 0
3 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
HELP ASAPPPP<br><br><br> please help me
Flauer [41]

Answer:

x=3, y=4

Step-by-step explanation:

hope this helps!

pls mark brainliest

4 0
2 years ago
I GIVEEE BRAINLILST TTT
Ainat [17]

Answer:nrtfggfnyhrthth vvsdgerghrf

Step-by-step explanation:

fghgf bncf njhgfnfnngfchfgngn fgnffbnfgggnfgn

7 0
3 years ago
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