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Stels [109]
3 years ago
11

Please help me with my question!!

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

10

Step-by-step explanation:

Since each ornament takes 1/4 of a piece of Bristol board we divide 2 1/2 by 1/4

2 1/2 = 5/2

(5/2)/(1/4) = 20/2 = 10

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8.032×10^-4 in standard form​
sdas [7]

Answer:

0.0008032

Step-by-step explanation:

Hope this helps!

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What is an equation of the line that passes through
lys-0071 [83]

Answer:

B

Step-by-step explanation:

For the perpendicular of an equation you need to flip the fraction and change the sign from positive to negative or if it's negative to positive. 3/2 is changed to -2/3 which when multiplied by -2 gives you 4/3 and 4/3+5/3 is equal to 3.

3 0
2 years ago
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
MaRussiya [10]

Answer:

the figure could be a rhombus because the 2 lines of symmetry bisect the angles

Step-by-step explanation:

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3 years ago
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What is the value of x ? <br> A : 15<br> B : 30 <br> C: 45 <br> D : 60
jenyasd209 [6]

Answer:

A

Step-by-step explanation:

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7 0
3 years ago
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Cone W has a radius of 8 cm and a height of 5 cm. Square pyramid X has the same base area and height as cone W. Paul and Manuel
sergij07 [2.7K]

This question is incomplete because it lacks the appropriate attachment containing the argument of Paul and Manuel

Kindly find attached the appropriate attachment necessary to solve this question.

The attachment was sourced online

Answer:

a) Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X

Step-by-step explanation:

From the above question, we are given two shapes: Cone W and Square Pyramid

Cone W: Radius = 8cm, Height = 5cm

Volume of a Cone = 1/3 πr²h

Where π = 3.14

Volume of Cone X = 1/3 × 3.14 × 8² × 5

= 334.93cm³

For Square pyramid X

Volume = 1/3 × Base Area × Height

Base Area of Cone W = Base Area of square pyramid X = πr²

Where π = 3.14

Base area = 3.14 × 8² = 200.96cm²

Height of Square pyramid X = Height of Cone W = 5cm

Volume of Square pyramid = 1/3 ×200.96cm² × 5cm

= 334.93cm³

Therefore, from my above calculation and compared with the arguments of Paul and Manuel, Option a) "Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X" is the correct option.

The reason why is because the correct formula for the volume of a square pyramid = 1/3 × Base area × Height

This was the formula Paul used.

Manuel on the other hand used the formula: Base Area × Height to find the volume of cone W. This formula is wrong.

Option a, is the correct answer.

4 0
3 years ago
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