The slope is 0 so it's a horizontal line parallel to the x-axis. All the values of y are the same. The line passes through the point (1,8), so y=8.
So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: 
Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: 
Now you can rewrite this as
, however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is
. Applying that here, we have
. x^4 + 5x^2 - 36 is completely factored.
Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 
Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 
Now you can rewrite the equation as
. 2x^2 + 9x - 5 is completely factored.
<h3><u>Putting it all together, your factored expression is

</u></h3>
Answer:
x^2-x+5
Step-by-step explanation:
(f-g)(x)=f(x)-g(x)
= (x^2 + 3) - (x - 2) (Don’t forget the -1 multiplies to the x AND -2
= x^2 + 3 - x + 2
=x^2-x+5
Step-by-step explanation:
13.5 is the difference of the length of the roads