split the right triangle from the trapezoid and solve for that right triangle first
<h3>
Answer: Choice A) 3.5</h3>
Work Shown:
The point (8,28) is the furthest to the right on the graph. We have x = 8 and y = 28 pair up here. Divide the y over the x
y/x = 28/8 = 3.5
side note: the tickmarks on the y axis go up by 4 each time
We can find the height of the altitude by the ratio of sin. See my attachment.
sin of angle = side in front of the angle / hypotenuse
sin x = height/distance
If the two pilot is rising in an hour, then the first distance is 400 miles, the second distance is 300 miles.
Find the height of first pilotheight/distance = sin x
height/400 = sin 30°
height = sin 30° × 400
height = 1/2 × 400
height = 200
Find the height of second pilotheight/distance = sin x
height/300 = sin 40°
height = sin 40° × 300
height = 0.642 × 300
height = 192
So the first pilot traveling 400 mph with 30° is more quickly to reach high altitude than the second pilot traveling 300 mph with 40°
These lines are perpendicular because y = -6 is a horizontal line with a slope of 0 and x = 6 is a vertical line with an undefined slope
Answer:
let, the days for 10 men be x
- 30/10=x/30
- 900=10x
- x=900/10
- x=90
so 10 men can complete the same work in 90days.
Hope it helps.