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Arisa [49]
3 years ago
6

Write the equation of a line perpendicular to y = 3 x-3 and whose y-intercept is (0,12).

Mathematics
2 answers:
sesenic [268]3 years ago
7 0

Answer:

y=-1/3x+12

Step-by-step explanation:

The slope of a line that is perpendicular to another is the negative reciprocal of the first. The slope of the line is 3 so the negative reciprocal will be -1/3.

Using the point-slope formula we can solve for the  equation of a line with a slope of -1/3 and a point of (0,12).

The point slope formula is

y-y1=m(x-x1).

y-12=-1/3(x-0) -------------->Distribute: y-12=-1/3x ---------------> Isolate the y by moving the 12 to the other side. y=-1/3x+12  

iren2701 [21]3 years ago
6 0
Y=1/3x+12

When writing an equation for a line that’s perpendicular, don’t forget to flip the slope to its reciprocal
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The best way to tackle this is to put the answer that you know into a binomial factor. So the solution is x = 4. The binomial factor is (x - 4)


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(x - 4)(  x    7) But what is its sign? The 28 is positive. So the 7 must be minus giving you

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I think if you remove the brackets, you will find that the middle term is - 19 (-12 - 7 = -19 ) which is exactly what it should be.


Answer (x - 4)(3x - 7)


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