Your answer is b. hope this helps :)
<u>These 2 equations has </u><u>no solution</u><u> and the equations are </u><u>independent</u><u> </u><u>of each other.</u>
What is liner equation with two variable?
- An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
- For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.
-10x² -10y² = -300 ----a
5x² + 5y² = 150 ---- b
While trying to solve this,
We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.
10x² + 10y² = 300 ----c
-10x² -10y² = -300 ---a
<u>Everything cutoff, we will </u><u>get 0</u><u>, and there is no solution to these equations.</u>
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Answer:
Step-by-step explanation:
This is an equation for which you need to solve for the value of the missing angle beta.
sin(15) has a decimal answer that you will find on your calculator. Finding that value makes this equation then
cosβ = .2588190451
Now use the 2nd button and then the cos button to find the angle that has a cos of that decimal. When you hit 2nd then cos, you should see this on your screen:
cos⁻¹ (
After that open parenthesis, enter you decimal then hit the enter button to find the angle. You should get 75, which is Choice B.
Step-by-step explanation:
(a) dP/dt = kP (1 − P/L)
L is the carrying capacity (20 billion = 20,000 million).
Since P₀ is small compared to L, we can approximate the initial rate as:
(dP/dt)₀ ≈ kP₀
Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.
20 = k (6,100)
k = 1/305
dP/dt = 1/305 P (1 − (P/20,000))
(b) P(t) = 20,000 / (1 + Ce^(-t/305))
6,100 = 20,000 / (1 + C)
C = 2.279
P(t) = 20,000 / (1 + 2.279e^(-t/305))
P(10) = 20,000 / (1 + 2.279e^(-10/305))
P(10) = 6240 million
P(10) = 6.24 billion
This is less than the actual population of 6.9 billion.
(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))
P(100) = 7570 million = 7.57 billion
P(600) = 20,000 / (1 + 2.279e^(-600/305))
P(600) = 15170 million = 15.17 billion
Answer:
for(j = n; j > 0; j--)
System.out.print(\"*\");
Step-by-step explanation:
-A for loop is a repetition control structure.
-It allows the efficiency to write a loop that would otherwise be written a couple of times.
-The output is a single line comprising n asterisks,
-The number of asterisks printed will be equivalent to the n-value declared.
