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belka [17]
2 years ago
14

Find the value of x. Round to the nearest tenth. 35° 16 x = [?]

Mathematics
1 answer:
Firlakuza [10]2 years ago
6 0

Answer:

nine point two.....9.2

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Find the volume of the figure.<br> A) 33 in^3 <br> B) 150 in^3 <br> C) 233 in^3 <br> D) 425 in^3
Nikolay [14]
5x5x5=125
12x3=36
36x3=108
108+125=233
233in^3 is the answer
8 0
3 years ago
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find the slope of the line that contains the following points A : [ 17 , -12 ] and [ 17 , 8 ] and B [ 6 , -2 ] and [ -3 , 1 ]
Svetradugi [14.3K]
1/9 because i you plug in two of the points into y2 -y1 over x2 -x1 thats what you get.
4 0
3 years ago
Find the area of the circle below. Use the formula <br> Use 3.14 for pi.
kirill [66]

Answer:

314

Step-by-step explanation:

Area is pie(r^2

10x10=100

100x3.14 is 314

6 0
2 years ago
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{(-2, 6), (-5, -1), (3, 7), (-5, 0)}<br> Domain:<br> Range:<br> Function?
just olya [345]

{(-2, 6), (-5, -1), (3, 7), (-5, 0)}

Domain: The domain is all the x-values (-2, -5, 3, -5)

Range: The range is all the y-values (6, -1, 7, 0)

Function: It's not a function because of the x-value -5 is repeating.

6 0
3 years ago
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At a certain high school, 15 students play stringed instruments and
Aleks [24]

Answer:

<em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N(A \cup B)' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N(A \cup B)' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

N(A\cap B) =0

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0

So, <em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

5 0
2 years ago
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