Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
Step-by-step explanation:
Nø of sample space, n(s) = 40
nø of unripe oranges, n (u) = 12
no of ripe oranges, n (r) = 40 - 12 = 28
Now
The probability that it is ripe is, P(E)
= n(r) / n(s)
= 28 / 40
= 7 / 10
Also the probability that it is unripe is, P(E)
= n(u) / n(s)
= 12 / 40
= 3 / 10
Hope it will help :)❤
Answer:
5x+3y-1475=0
Step-by-step explanation:
if this helps please mark brainliest <3
Answer:
The answer is C because the two figures are not congruent.
