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Archy [21]
3 years ago
15

Ty has 5 goats and 19 carrots. He gives each goat the same number of carrots, and he uses as many carrots as he can. How many ca

rrots does Ty give each goat? How many carrots are left?
Mathematics
1 answer:
velikii [3]3 years ago
6 0

Each goat gets 3 carrots.

After giving 3 carrots to each of the goat, 4 carrots are left with Ty in total.

Step-by-step explanation:

Here, the total number of carrots  = 19

The total number of goats  = 5

So, in the given condition:

19 is the DIVIDEND

5 is the DIVISOR

Now, dividing 19 by 5, we get:

19  = 5 x 3 +  4

Here,  3 = Quotient

4 = Remainder

So, by the given equation. we can say that:

Each goat gets 3 carrots.

After giving 3 carrots to each of the goat, 4 carrots are left with Ty in total.

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What's the probability of the compound event for. A bag contains 4 red, 8 blue, 6 yellow and 2 green marbles. Maria selects a ma
Nataly [62]

Given:

Number of red marbles = 4

Number of blue marbles = 8

Number of yellow marbles = 6

Number of green marbles = 2

To find:

The probability of getting a blue marble then a red marble, i.e., P(blue, red).

Solution:

Using the given information,

The total number of marbles = 4+8+6+2

                                                = 20

Probability of getting a blue marble in first draw is

P(Blue)=\dfrac{\text{Number of blue marbles}}{\text{Total number of marbles}}

P(Blue)=\dfrac{8}{20}

P(Blue)=\dfrac{2}{5}

Maria selects a marble, puts it back and then selects a second marble. It means the total number of marbles remains the same.

P(red)=\dfrac{\text{Number of red marbles}}{\text{Total number of marbles}}

P(red)=\dfrac{4}{20}

P(red)=\dfrac{1}{5}

Now, the probability of getting a blue marble then a red marble is

P(blue,red)=\dfrac{2}{5}\times \dfrac{1}{5}

P(blue,red)=\dfrac{2}{25}

Therefore, the required probability P(blue, red) is \dfrac{2}{25}.

5 0
3 years ago
Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
3 0
3 years ago
Read 2 more answers
Factor 12m^2n^2-8mn+1
Vika [28.1K]
12m²n² -8mn +1


[6mn-1]•[ 2mn-1]

[ 6mn•2mn + 6mn•-1 + -1•2mn +-1•-1]

= [ 12 m²n² -6mn -2mn +1]

= [ 12m²n2-8mn+1]





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6 0
3 years ago
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g
givi [52]

Given :

An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.

To Find :

How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.

Solution :

Mass of copper in 50 gm alloy = 50\times 0.12 = 6\ gram.

Mass of copper in 78 gm alloy = 78\times 0.98 = 76.44\ gram.

Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.

Percentage of copper in resulting mixture :

\%=\dfrac{82.44}{50+78}\\\\\%=64.4\ \%

Hence, this is the required solution.

8 0
4 years ago
Translate this sentence into an equation. 62 is the sum of 12 and Chrissy's age. Use the variable c to represent Chrissy's age.
Greeley [361]
62= 12+c

Which your answer is 50 cause if you take 62 and subtract it to 12 it's 50. So 50 + 12 = 62
5 0
4 years ago
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