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irina [24]
3 years ago
11

Pls help I’m failing I’ll brainlest

Mathematics
1 answer:
LenKa [72]3 years ago
7 0

Answer:

6x

Step-by-step explanation:

Since 2 sides are equal to 3x-3, multiply 3x-3 by 2.

=6x-6

Subtract 18x+6 - 6x-6

= 12x

Since 2 there are 2 sides missing, 12x divided by 2

=6x

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Help it’s confusing
noname [10]

Answer:

I think is C like I said not quite sure...

8 0
3 years ago
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Can someone help me with this problem please? Thank you!
Olenka [21]

Answer:

50

Step-by-step explanation:

since the Pythagorean theorem is

c= √a^2+b^2

b is the bottom line (48)

a is the right line (14)

c is the top line (c)

plug that in

c = √14^2 + 48^2

then do the exponets

14^2 = 14 * 14 = 196

48^2 = 48 * 48 = 2304

then add them together

196 + 2304 = 2500

c = √2500

the sqrt of 2500 is 50 (50 * 50 = 2500)

c = 50

your answer is 50

hope this helps:)

6 0
2 years ago
Read 2 more answers
5*9 (sqrt 10)^3= Help please
Nikitich [7]
Use BODMAS or BIDMAS (Brackets, over Indices, Division, Multiplication, Addition, the Subtraction, this tells you which order to do things in)

As you cant do √10 in the brackets you do the indices, so (√10)³
Split this up to make it easier
(√10)³= √10 x √10 x √10 = 10√10

You the multiply this by 9

9 x 10√10 = 90√10

then multiply by 5

5 x 90√10 = 450√10 = 1423.024947 (using calculator)
7 0
3 years ago
hmu if ur bored and wana talk. age limit tho. cant be younger than 14 or older than 19 dont wanna talk to creepy people lol
Orlov [11]

Answfunny lol lol

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do you simplify this
Dafna11 [192]

Top:

x / (x + 1) - 1 / x

= [x^2 - (x +1)] / x(x+1)

= (x^2 - x - 1 ) / x (x+1)

Bottom:

x / (x + 1) + 1 / x

= [x^2 + (x +1)] / x(x+1)

= (x^2 + x + 1 ) / x (x+1)

Now you have:

(x^2 - x - 1 ) / x (x+1)

----------------------------

(x^2 + x + 1 ) / x (x+1)

= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )

= (x^2 - x - 1 ) /(x^2 + x + 1 )

Answer:

x^2 - x - 1

---------------------

x^2 + x + 1

7 0
3 years ago
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