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3 years ago

Find the 6th term in the sequence of 11,33,99,297...

Mathematics

1 answer:

Keith_Richards [23]3 years ago

5 0

Answer:

$2673$

Step-by-step explanation:

In order to find the answer to this question you must find the rule and then keep applying that rule in till you get to the 6th term of the sequence.

$11,33,99,297$

$R=\times3$

$297\times3=891$

$891\times3=2673$

$=2673$

Hope this helps.

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A landscaper, who just completed a rectangular flower garden measuring 15 feet in length by 7 feet in width, orders 1 cubic ya

grin007 [14]

The width of the border will be 0.1648... ft or 1.9786... inches.

Explanation

Lets assume, the width of the border is $x$ ft.

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$\frac{11}{3}[(15+2x)(7+2x)-105] = 27\\ \\ 11(105+44x+4x^2 -105)=81\\ \\ 11(4x^2+44x)=81\\ \\ 44x^2+484x-81=0$

Using quadratic formula....

$x= \frac{-484+/-\sqrt{484^2-4(44)(-81)}}{2(44)}\\ \\ x= \frac{-484+/-\sqrt{234256+14256}}{88}\\ \\ x= \frac{-484+/-\sqrt{248512} }{88}\\ \\ x= 0.1648...$

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3 years ago

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Answer:

The table in the attached figure

Step-by-step explanation:

The picture of the question in the attached figure N 1

we have

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For x=-1 ---> $y=-3(-1)+5=8$

For x=-0 ---> $y=-3(0)+5=5$

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The table in the attached figure N 2

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