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zlopas [31]
2 years ago
14

John leaves his house at Sam. It

Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

7:52am

Step-by-step explanation:

John leaves by 5:00am

He gets to school after 35 minutes

The time now is 5:00 + 0:35 = 5:35am

After 2 hours and 2 mins of lectures, the time is 5:35 + 2:02 = 7:37am

After 15 minutes, the time is 7:37 + 0:15 = 7:52am

Therefore the answer is 7:52am.

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A.

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1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)




b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
distance from 6 to 20 is 14, 14/7=2, 2 times 5=10
distance from 12 to 12=0, so same coordinate
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c.
2+3=5

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3 years ago
Can someone help me? When I put 4.50 x 33.47 in the calculator it gives me a weird number and I have a test tomorrow! I really w
leva [86]
Use long multiplication to evaluate.
150.615
5 0
3 years ago
Read 2 more answers
Which expression simplifies to 8x^5?
tamaranim1 [39]

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Step-by-step explanation:

8 0
2 years ago
I need help with number 2 don’t understand it. someone help plz.
Sholpan [36]

I would say solve each diameter equation and order them fromleast to greatest, for example

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Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
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