Answer:
a) WS, ZV, YU
b) VU
c) ZW
d) WXY
e) None
f) TU, TV, UV, XY, XZ, YZ
g) SW, VX, VZ, WX, WZ, YZ
Step-by-step explanation:
A prism is a polyhedron that has:
- Two bases that are congruent and parallel to each other.
- Lateral sides that are parallelograms and link the two bases.
- Height that is the distance between the two bases.
From inspection of the give diagram, the figure appears to be a quadrilateral prism with bases STUV and WXYZ.
<u>Parallel line segments</u>
- Parallel line segments lie on parallel lines.
- Parallel lines are lines on a plane that <u>never meet</u> and are the <u>same distance apart</u>.
a) Segments parallel to XT:
b) Segments parallel to ZY:
c) Segments parallel to VS:
<u>Planes</u>
- A plane is a flat, two-dimensional surface that extends into infinity.
- A plane can be named by the letters naming three non-collinear points in the plane.
- Parallel planes are planes that never intersect.
d) Planes parallel to plane STU:
e) Planes parallel to plane UVZ:
<u>Skew lines</u>
Skew lines are a pair of non-coplanar lines that:
- Do <u>not</u> intersect.
- Are <u>not</u> parallel to each other.
f) Segments skew to SW:
g) Segments skew to UT:
I believe it is 15 I am using trigonometry but I’m not 100% sure
Answer:
The first five terms of the recursive sequence are;
5, 12, 19, 26, 33
Step-by-step explanation:
The given sequence is presented as follows;
aₓ = a₍ₓ ₋ ₁₎ + 7
The first term of the sequence, a₁ = 5
Therefore, we have;
a₂ = a₍₂ ₋ ₁₎ + 7 = a₁ + 7 = 5 + 7 = 12
a₃ = a₍₃ ₋ ₁₎ + 7 = a₂ + 7 = 12 + 7 = 19
a₄ = a₍₄ ₋ ₁₎ + 7 = a₃ + 7 = 19 + 7 = 26
a₅ = a₍₅ ₋ ₁₎ + 7 = a₄ + 7 = 26 + 7 = 33
The first five terms of the recursive sequence are therefore;
5, 12, 19, 26, 33.
Number 1 = x
Number 2 = y
x = 12y + 6
x + y = 214
You can do multiple methods here. (I am going to do substitution)
So substitute the x equation into the other equation
(12y + 6) + y = 214
13y = 208
y = 16
plug that into an equation to get x
x = 12(16) + 6
x = 198
You can check and see 16 + 198 =214